2. Joy would like to enter both the pie eating contest and the egg toss.
3. If Joy wins the pie eating contest, then she will not be allowed to enter the egg toss.
4. Jenny would like to enter the somersault race and the pie eating contest, but she can’t because they are both at the same time. So she will enter the pie eating contest, unless she is wearing her favorite shirt with all the sparkles. If she is wearing that shirt, she will enter the somersault race instead.
5. If Joy enters the egg toss, then Todd will get egg in his hair. (If she doesn’t enter the egg toss, his hair will stay clean and fresh.)
6. The only person in the whole world who can beat Joy in the pie eating contest is Jenny.
7. The only person in the whole world who can beat Todd in the somersault race is Jenny.
8. Everyone who enters the pie eating contest ends up with whipped cream on their noses.
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Based on the above facts, which of the following conclusions must be true? (There may be more than one.)
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a: If Jenny wears her sparkly shirt, Todd will win the somersault race.
b: If Jenny’s shirt doesn’t have sparkles, Todd won’t win the somersault race.
c: If Joy wins the pie eating contest, Todd will win the somersault race.
d: If Todd has egg in his hair, Jenny will have whipped cream on her nose.
e: If Joy has whipped cream on her nose, Todd will have egg in his hair.
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(There is no clue or hint for this problem.)
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Clues
In general:
Remember that in solving arithmetic problems you work from right to left. So when I speak of the “first column” I mean the “one’s column,” or the column furthest to the right. When I speak of the “last column” I mean the column furthest to the left.
When solving the arithmetic problems, be careful not to confuse the letter o with the number zero, or the letters i or l with the number one.
Some of the clues give you several steps to follow. Make sure you understand the first step, before moving on to the next one.
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Problem 1:
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Notice that b + b has to equal a two digit number. That means that b has to be 5 or more. But the key to the problem is the circled s. To begin the problem, you have to figure out what number the circled s must represent. Then you will change all s’s to that number and solve for y.
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