More Sideways Arithmetic From Wayside School (Wayside School 2.60)

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In the first column notice that two l’s + t = t (or a number that ends in t.) That means that l + l is either zero or ten. The second column should answer that question.

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Problem 14:

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Begin with the letter t. Don’t forget there isn’t an 8 anywhere in the problem. That is essential in figuring out e and a.

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Problem 15:

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Start with one + one = zero. Notice that in the first column, e + e = o, and in the third column, o + o = e. How is that possible?

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Problem 16:

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Start with Z. That should then give you the circled M and then the circled S. As you work your way through the problem you should be able to get all the letters except for the letters N and R. That is where the letter Q comes in. With the letter Q all 10 digits are used in the problem. And don’t forget Q is more than N.

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Problem 17:

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This problem also uses all ten digits. It may be helpful to write out the numbers, 0 1 2 3 4 5 6 7 8 9, and then as you figure out the letters, write the letter under the corresponding number. For example, you should figure out right away that w = 1. So write the letter w under the number 1. As you continue to work the problem it will become useful to be able to look at your list so that you can clearly see what numbers are still available.

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Problem 18:

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Again it will be helpful to make a list of the numbers, even though only nine digits are used in this problem. The key to get you started is noting that in the third column, i + e = e, yet i cannot be zero, because of the last column.

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