Sideways Arithmetic From Wayside School (Wayside School 2.50) - Page 38

Spelling

Problem 1 Answer:

e = 7;llf = 1;gl = 2;llo = 4.

Problem 2 Answer:

a = 7;lle = 8;llg = 9;llp = 1.

Problem 3 Answer:

a = 4;lle = 8;llr = 2;lls = 1;llw = 6.

Problem 4 Answer:

o = 5;llp = 0;llt = 2.

Problem 5 Answer:

e = 1;llh = 8;lll = 0;lls = 9.

Problem 6 Answer:

m = 7;llo = 5;llp = 8;lly = 1.

Problem 7 Answer:

a = 7;llr = 0;lls = 8;llt = 9;llu = 5;lly = 1.

Problem 8 Answer:

a = 6;lle = 2;lls = 1.

Problem 9 Answer:

o = 0;llp = 5;lly = 1.

Problem 10 Answer:

d = 9;lle = 5;lll = 7;llo = 0;lls = 2;llw = 1.

Problem 11 Answer:

c = 2;lld = 3;lle = 6;lli = 9;llp = 0;lls = 1.

g

Chapter 2

Numbers

Problem 12 Answer:

e = 7; n = 6;llo = 4;llt = 9;llw = 3.

Problem 13 Answer:

A three-digit number plus a three-digit number cannot equal a five-digit number.

Tags: Louis Sachar Wayside School Fiction
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